Point slope Equation for Straight Lines - Derived in Four Cases
In this lesson, we explain how equations for lines in
the coordinate plane follow from similarity of triangles in the
plane.
We will see or show below that points (x,y) on non-vertical line L
satisfy point-slope equation
y - y1 = m(x-x1)
where m the slope is a proportionality constant, a real number, and
(x1, y1) is a given point on the line. The equation
of vertical line through a point (x1, y1) is
x = x1
The derivation of the above two equations for four cases
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Downward Slanted Line: y - y1 = m(x-x1)
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Upward Slanted Line: y - y1 = m(x-x1)
-
Horizontal Line: y - y1 = 0
-
Vertical Line: x - x1= 0
follow below.
Downward Slanted Lines - Case 1 of 4
For a downward slanting line, every pair of triangles with hypotenuse on
the line and sides parallel to the coordinate axes are similar.
Similarity follows because the line through the hypotenuses serves as
a transversal for the parallel lines through the horizontal and vertical
sides. From latter corresponding angles are equal.
Two triangles one with sides lengths given by
lower case and another with lengths in uppercase characters.
Similarity implies corresponding sides are proportional. That is for some
constant q
drop = q DROP and run = q RUN
The latter gives
drop run
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=
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q*DROP
q*RUN
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=
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DROP
RUN
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Hence the drop over run ratios for the triangles are equal.
The common value of these ratios provides a proportionality constant k
such that the drop in each triangle is proportional to the run of each
triangle.
Calculation of the drop over run proportionality constant.
The proportionality constant k can be computed from any pair of points
(x1, y1) and (x2, y2) are the
line.
From the diagram, the drop over rise proportionality constant is
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k
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=
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DROP
RUN
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=
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That is drop over rise proportionality constant k is given by the
calculation
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k
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=
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Equation that follows from proportionality
Now if (x, y) is on the line with drop over run proportionality constant
k and (x1, y1) is a point on the with x1
< x on the line we have a situation like the following.

Diagram for x1 < x
For the run and drop triangle determine by the two points (x,y) and
(x1, y1), the proportionality constant
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k
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=
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Therefore (x, y) satisfies the equation
y1 - y = k(x-x1)
or equivalently
y - y1 = -k(x-x1)
where (x1, y1) and k are unknown. The change of
notation m = -k puts this equation in the sought after form
y - y1 = m(x-x1)
The value of m is called the slope of the line. Here m = -k is
negative as the drop over run ratio or proportionality constant k is
positive - a situation implied by non-zero drop. Positive slopes will be
seen below in the case of upward slanting lines.
Exercise: Show the same equation follows if (x, y) and
(x1, y1) are two points on a line with
proportionality constant k = -m with x > x1

Diagram for x1 > x
Lines Slanted Upward - Case 2 of 4
For a upward slanting line, every pair of triangles with hypotenuse on
the line and sides parallel to the coordinate axes are similar.
Similarity follows because the line through the hypotenuses serves as
a transversal for the parallel lines through the horizontal and vertical
sides. From latter corresponding angles are equal.
Similarity implies the rise over run ratios for the triangles are equal.
The common value of these ratios provides a proportionality constant K
such that the rise in each triangle is proportional to the run of each
triangle.
Calculation of the Proportionality Constant
The proportionality constant K can be computed from any pair of points
(x1, y1) and (x2, y2) are the
line.
Therefore
Equation that follows from proportionality
The assumption that (x,y) is on the line in place of (x ,y)
leads to the equation
where the proportionality constant K is known. The latter equation in
turn implies
y - y1 = K(x-x1)
The latter gives an equation satisfied by all points on the line through
point (x1, y1) with rise over run proportionality
constant K. The point-slope equation for a line
y - y1 = m(x-x1)
appears if we let m = K.
Horizontal Line - Case 3 of 4
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A horizontal line in the coordinate plane is parallel to the
x-axis.
All points on the line have the same y-coordinate while the
x-coordinate can have any value. If (x1, y1)
is a point on a horizontal line then another point (x,y) is on the
line when and only when y = y1 . This equation restricts
y to the constant value y1 with out restricting the
value of x. So the equation y = y1 .or equivalently y -
y1 = 0 describes the horizontal line through
(x1, y1).
The latter equation y - y1 = 0 has the form
y - y1 = m(x-x1)
if we put m = 0 as zero time (x-x1) gives 0 regardless
of the values of x and x1.
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Vertical Line - Case 4 of 4.
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A vertical line in the coordinate plane is parallel to the y-axis.
All points on the line have the same x-coordinate
while the y-coordinate can have any value. If (x1,
y1) is a point on a vertical line then another point
(x,y) is on the line when and only when x = x1 . This
equation restricts x to the value x1 with out
restricting the value of y. So the equation
x = x1
describes the vertical line through (x1, y1).
We are done.
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Conclusion
For each non-vertical slanted line through a point (x1,
y1), there is a constant m called the slope of the line
such that every point (x,y) on the line satisfies the equation
y - y1 = m(x-x1)
Note if we call x-coordinate difference (x-x1) a runand
vertical line difference y - y1 a rise, differences
that may be positive, zero or negative, the point slope equation say the
rise is proportional to the run with proportionality constant m.
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For each straight line, its slope m is the
proportionality constant linking the rises to
runs for any two points on the line.
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slope m =
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Dy
Dx
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=
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y2-y1
x2-x1
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=
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rise
run
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|
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Two points are usually needed to compute the slope. For a
straight line segment, the slope m is a constant of
proportionality between Dy = y-y1 and Dx = x-x1. The change Dy in y (the rise) is
proportional to the change in Dx (the run) in x, and so
Dy = m Dx
or equivalently
y-y1 = m(x-x1)
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For each point on the line (x1, y1),
there is a point-slope equation. But given (x1,
y1), we can take the equation y - y1 =
m(x-x1) and express y in terms of x. That operation
yields y = mx +b where b = y1- mx1. Now x
= 0 in y = mx +b implies y = b. So the point (0,b) gives the
lines intersetion with the y-axis. Since the line is not
vertical, it has only one point of intersection. So b b =
y1- mx1 is unique and independent of the
choice of (x1, y1). The convention that
we rewrite the point-slope form
y - y1 = m(x-x1)
as y = mx+b by solving for y provides the unique y-intercept
slope equation of the line L.
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Remark: If we know points (x1, y1) and
(x2, y2) belong to non-vertical line with equation
y - y1 = m(x-x1)
then (x,y) = (x2, y2) must satisfy the equation. So
y2 - y1 = m(x2-x1)
Thus the value of m, known or not, must be given by the equation
where the RISE = y2 - y1 and RUN =
x2-x1 are allowed to be real numbers. The slope m
provides the (signed) rise over (signed) run proportionality constant or
ratio for the line.
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